What is the coefficient of static friction? - static friction pics
A paperback 310g is based on a manual 1.2kg. A force applied to textbooks, and the two books together to accelerate the remaining 96 cm of 0.42. The manual is intended then brought to a standstill at 0.33, where the sheet pocket book. In which area is the coefficient of static friction between the two books is located?
Sunday, January 24, 2010
Static Friction Pics What Is The Coefficient Of Static Friction?
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The friction force is the acceleration of the bag. The frictional force required to accelerate the paperback, which is then
ReplyDeleteFR1 = (0.31) * (0.92 / 0.42) = 0.67 N
The friction force needed to accelerate the de-Buch and then stop
EN2 = 0.31 * (0.92 / 0.33) = 0.86 N
I assume that the velocity is 96 cm / s. The maximum force of static friction
P. Max = N = mg, we
In your problem, Fr1 \\ \\ \\ \\ \\ \\ \\ \\ u0026lt, Max P. and FR2> Frmax the
\\ \\ \\ \\ FR1 \\ \\ \\ \\ u0026lt; Frmax \\ \\ \\ \\ \\ \\ \\ \\ u0026lt; Fk2
0.67 \\ \\ \\ \\ \\ \\ \\ \\ u0026lt; Frmax \\ \\ \\ \\ \\ \\ \\ \\ u0026lt 0.86
or
0.67 \\ \\ \\ \\ \\ \\ \\ \\ u0026lt; us mg \\ \\ \\ \\ \\ \\ \\ \\ u0026lt 0.86
mg of everything that we share
0.67/mg \\ \\ \\ \\ \\ \\ \\ \\ u0026lt and we u0026lt \\ \\ \\ \\ \\ \\ \\ \\; 0.86/mg
0.67 / (0.31 * 9.8) \\ \\ \\ \\ \\ \\ \\ \\ u0026lt and we \\ \\ \\ \\ \\ \\ \\ \\ u0026lt; 0.86 / (0.31 * 9.8)
0.22 \\ \\ \\ \\ \\ \\ \\ \\ u0026lt and we \\ \\ \\ \\ \\ \\ \\ \\ u0026lt, 0.28
and this is your area for the coefficient of static friction us